Question
A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.620 s. How much time passes during his entire trip from the top down to the water? Ignore air resistance.
Answers
Henry
d1 = 0.5g*t^2 = 4.9*0.62^2 = 3.04 m = 1/2 the distance.
d = 0.5g*t^2 = 2*3.04 = 6.08 m.
4.9*t^2 = 6.08
t^2 = 1.24
t = 1.114 s. passed during entire trip.
d = 0.5g*t^2 = 2*3.04 = 6.08 m.
4.9*t^2 = 6.08
t^2 = 1.24
t = 1.114 s. passed during entire trip.