Asked by kanza
An airplane is flying with a velocity of 600 km/hr and at a height of 1960 m. When it is vertically above a point A on a ground, a bomb is released frm it. The bomb strikes the ground at pt B. The distance AB is ____ ?
Answers
Answered by
bobpursley
time to fall:
1969=1/2 g t^2
t= sqrt(2*1980/g)
now, horizontal distance traveled during that time t
AB= 600km/hr*t(inseconds)*1/3600 in meters.
1969=1/2 g t^2
t= sqrt(2*1980/g)
now, horizontal distance traveled during that time t
AB= 600km/hr*t(inseconds)*1/3600 in meters.
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