Asked by Mary
Two cars, A and B, travel in a straight line. The distance of A from the starting point is given as a function of time by xA(t)=αt+βt^2, with α=2.60m/s and β=1.20m/s^2. The distance of B from the starting point is xB(t)=γt^2−δt^3, with γ=2.80m/s^2 and δ=0.20m/s^3.
Which car is ahead just after they leave the starting point?
At what time(s) are the cars at the same point?
First time taking physics, appreciate any help!
Which car is ahead just after they leave the starting point?
At what time(s) are the cars at the same point?
First time taking physics, appreciate any help!
Answers
Answered by
bobpursley
at the starting point, t is very small. If A is ahead, then A-B must be negative.
A-B=αt+βt^2-γt^2+δt^3. For very small t, the first term will predominate. A is ahead.
When is A-B=0?
2.6t+1.2t^2-2.8t^2+.2t^3=0
combine the t^2 terms.
then factor out a t, you are left with a quadrataic equation, solve it.
A-B=αt+βt^2-γt^2+δt^3. For very small t, the first term will predominate. A is ahead.
When is A-B=0?
2.6t+1.2t^2-2.8t^2+.2t^3=0
combine the t^2 terms.
then factor out a t, you are left with a quadrataic equation, solve it.
Answered by
yurina
5.7320
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Saksham
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k sri harshini
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