Asked by hezal

sledge of mass 80 kg moves over the frozen surface of a lake with a velocity of 30m/s and comes to rest in 5s. find frictional force between the lake and sledge

Answers

Answered by MathMate
Average acceleration
=(0-30) m/s ÷ 5 s
= -6 m/s²

Force
= ma = 80 kg * (-6 m/s²)
= -480 N (resistive force)
Answered by Rachna
F=ma
F=80×-30/5
F=80×6=-480N
Declaration=change in velocity
/time -30/5=-6mssquare

There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions