Question
A 6.0 kg mass moves along an inclined plane that makes an angle of 36 degrees with the horizontal. The mass is connected by a cable to a second mass of 10.0 kg, which is suspended over a frictionless, massless, pulley and is free to move. The second mass of 10.0 kg falls at a constant velocity. a) What are the magnitude and direction of the frictional force exerted by the 6.0 kg mass on the plane? b) What is the coefficient of kinetic friction between the 6.0 kg mass and the inclined plane?
Answers
The cable tension equals the weight of the 10 kg mass, since it falls at constant velocity.
For the 6 kg mass, the cable tension equals its weight component down the slope, minus the friction force.
Use that fact to solve for the friction force and coefficient.
For the 6 kg mass, the cable tension equals its weight component down the slope, minus the friction force.
Use that fact to solve for the friction force and coefficient.
eachus?
A sign is attached to the side of a building using a beam and a cable. The sign weighs 430 pounds, and the angle between the cable and the beam is 20 degrees. You may ignore the weights of the beam and the cable---use only the weight of the sign in your calculations.
Related Questions
An object of mass 10.0 kg is released from the top of an inclined plane which makes an angle of incl...
A person of mass 84kg is at rest at the bottom of an inclined plane that makes an angle of 30 degree...
A block of mass m is initially at rest at the top of an inclined plane with a height = 4.4 m which m...
Two 1kg blocks rest on opposite sides of the double inclined plane. One inclined planes makes an ang...