Asked by anonymous
I know I need to show my work but the problem is that I don't even know where to begin. I am taking an online physics class with a teacher that is not willing to help. So any guidance would be much appreciated.
Consider the two vectors:
F1: (220N, 41°), F2: (50N, 139°)
The angles are measured from the positive x axis with the counter-clockwise angular direction taken as positive.
1.) What is in N, the x-component of the resultant vector F?
2.)What is in N, the y-component of the resultant vector F?
3.)What is in N, the magnitude of vector F?
Consider the two vectors:
F1: (220N, 41°), F2: (50N, 139°)
The angles are measured from the positive x axis with the counter-clockwise angular direction taken as positive.
1.) What is in N, the x-component of the resultant vector F?
2.)What is in N, the y-component of the resultant vector F?
3.)What is in N, the magnitude of vector F?
Answers
Answered by
bobpursley
I assume F=F1+F2
1 add the x components: 22Ocos41+50cos139
2 add the y components: 220sin41+50sin139
3 for the magnatude, then Magnitude=sqrt(x^2+y^2)
1 add the x components: 22Ocos41+50cos139
2 add the y components: 220sin41+50sin139
3 for the magnatude, then Magnitude=sqrt(x^2+y^2)
Answered by
anonymous
thank you! that helps so much!I was able to work other questions that were similar to this question thanks to you :)
What is in degrees as measured from the positive x in the counter-clockwise angular direction the direction of vector F?
What is in degrees as measured from the positive x in the counter-clockwise angular direction the direction of vector F?
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