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A microscopic droplet of ink in an ink-jet printer is deflected onto the paper by a force of 2.34×10-4 N. If the field causing the deflection is 6.62 kN/C, what is the charge on the droplet?

What equation do I use to solve and What does each value mean in the equation? thnks
11 years ago

Answers

Brad
F=Eq
q=F/E
q=2.34^-4/6620
11 years ago

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