Asked by charles
In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
If you burn 54.8 g of hydrogen and produce 4.90 × 102 g of water, how much oxygen reacted?
If you burn 54.8 g of hydrogen and produce 4.90 × 102 g of water, how much oxygen reacted?
Answers
Answered by
DrBob222
2H2 + O2 ==> 2H2O
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols O2.
Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols O2.
Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.
Answered by
charles
In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
If you burn 54.8 g of hydrogen and produce 4.90 × 10^2 g of water, how much oxygen reacted?
If you burn 54.8 g of hydrogen and produce 4.90 × 10^2 g of water, how much oxygen reacted?
Answered by
DrBob222
Follow my directions to get the answer or explain in detail what you don't understand about the directions. Retyping the question won't get it.
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