Question
In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
If you burn 54.8 g of hydrogen and produce 4.90 × 102 g of water, how much oxygen reacted?
If you burn 54.8 g of hydrogen and produce 4.90 × 102 g of water, how much oxygen reacted?
Answers
2H2 + O2 ==> 2H2O
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols O2.
Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols O2.
Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.
In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
If you burn 54.8 g of hydrogen and produce 4.90 × 10^2 g of water, how much oxygen reacted?
If you burn 54.8 g of hydrogen and produce 4.90 × 10^2 g of water, how much oxygen reacted?
Follow my directions to get the answer or explain in detail what you don't understand about the directions. Retyping the question won't get it.
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