Question

The combustion of 1.0 mol of sucrose liberates 5.65 x 10^3 KJ of heat. A calorimeter that has a heat capacity of 1.23 KJ/°C contains 0.60kg of water. How many grams of sucrose could be burned in the calorimeter to raise the temperature of the calorimeter and its content from 23°C to 27°C?

Answer 1

How many J are need to raise the T? That's
Total Q = q(water) + q(cal)
q(water) = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q(water) = 600 g x 4.184J/g*C x (27-23) = abut 10,000 J but that's an estimate and you should do it and all the calculations that follow much more carefully.
q(cal) = 1,230 x dT = 1,230 x 4 = about 5,000 J
Q = about 15,000 J = 15 kJ.
You know 1 mol sucrose (that's 342 g sucrose) will liberate 5.65E3 kJ. So how many grams sucrose will it take? That's
342 g sucrose x (15 kJ/5.65E3 kJ) = ? g sucrose.
Remember all of these numbers are estimates.