Asked by bob
what is the equation of a parabola whose vertex is (6,0) and whose graph is half as tall as y=x^2 and opens upside down
Answers
Answered by
Steve
Vertex at (6,0)
y = (x-6)^2
half as tall
y = 1/2 (x-6)^2
flipped
y = -1/2 (x-6)^2
y = (x-6)^2
half as tall
y = 1/2 (x-6)^2
flipped
y = -1/2 (x-6)^2
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