Question
At some temperature, the reaction
PCl3(g)+Cl2(g)====PCl5(g)
is at equilibrium when the concentration of PCl3, Cl2, and PCl5 are 10, 9.0, and 12 mol/L,
respectively. Calculate the value of Kc for this reaction at that temperature.
PCl3(g)+Cl2(g)====PCl5(g)
is at equilibrium when the concentration of PCl3, Cl2, and PCl5 are 10, 9.0, and 12 mol/L,
respectively. Calculate the value of Kc for this reaction at that temperature.
Answers
It is given that the reaction at the given temperature is in equilibrium.
Next check if the reaction is homogeneous: all gases, so homogeneous.
Now denote the stoichiometric coefficients by a,b and c for the reactants and products respectively (all equal to 1 in this case).
then Kc is given by:
Kc=[PCl5]^c/([PCl3]^a [Cl2]^b)
[] means concentration (mol/L).
Next check if the reaction is homogeneous: all gases, so homogeneous.
Now denote the stoichiometric coefficients by a,b and c for the reactants and products respectively (all equal to 1 in this case).
then Kc is given by:
Kc=[PCl5]^c/([PCl3]^a [Cl2]^b)
[] means concentration (mol/L).
Note that the coefficients in this equation are a, b, and c, and those have a value of 1 in this instance.
thanks =)
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