Question
I aked the instructor about that problem that looked like this:
(w-(1)/(4))^2
and he said that what i thought was right. which was :
the answer:w^2-(1)/(2)w+(1)/(6)
Yes, that's right. I just thought your way of getting the answer was more complicated than it could have been.
With the placement of the parentheses in your answer I can't tell what you have, but I can tell you for sure that what Belinda wrote yesterday; i.e.,
[(w-1)/4]<sup>2</sup> =
(w<sup>2</sup> -2w +1)/16 is correct. That answer may be modified somewhat by certain arithmetic procedures but squaring w-1 MUST give, at least as a first step, w<sup>2</sup> -2w +1.
see dr.bob222
then why did the instructor say that this was wrong about
w2 -2w +1
he said it had to be:
w squared and negative one half w plus one over sixteen.
<b>We aren't working the same problem. And the reason for that is that you didn't use parentheses correctly. You are working this problem. </b>
(w-(1)/(4))^2
<b> Written as you should have written it is
[w-(1/4)]<sup>2</sup>
</b><I> That give you
w<sup>2</sup> - 0.5w + 1/16 which agrees with your previous answer and the teacher's answer.</I>
<b>I worked this one</b>
[(w-1)/4]<sup>2</sup>
<b>which gives the answer I posted yesterday.</b>
(w<sup>2</sup> -2w + 1)/16
<I>I hope this clears things up.
(w-(1)/(4))^2
and he said that what i thought was right. which was :
the answer:w^2-(1)/(2)w+(1)/(6)
Yes, that's right. I just thought your way of getting the answer was more complicated than it could have been.
With the placement of the parentheses in your answer I can't tell what you have, but I can tell you for sure that what Belinda wrote yesterday; i.e.,
[(w-1)/4]<sup>2</sup> =
(w<sup>2</sup> -2w +1)/16 is correct. That answer may be modified somewhat by certain arithmetic procedures but squaring w-1 MUST give, at least as a first step, w<sup>2</sup> -2w +1.
see dr.bob222
then why did the instructor say that this was wrong about
w2 -2w +1
he said it had to be:
w squared and negative one half w plus one over sixteen.
<b>We aren't working the same problem. And the reason for that is that you didn't use parentheses correctly. You are working this problem. </b>
(w-(1)/(4))^2
<b> Written as you should have written it is
[w-(1/4)]<sup>2</sup>
</b><I> That give you
w<sup>2</sup> - 0.5w + 1/16 which agrees with your previous answer and the teacher's answer.</I>
<b>I worked this one</b>
[(w-1)/4]<sup>2</sup>
<b>which gives the answer I posted yesterday.</b>
(w<sup>2</sup> -2w + 1)/16
<I>I hope this clears things up.