Question

I aked the instructor about that problem that looked like this:

(w-(1)/(4))^2

and he said that what i thought was right. which was :

the answer:w^2-(1)/(2)w+(1)/(6)

Yes, that's right. I just thought your way of getting the answer was more complicated than it could have been.

With the placement of the parentheses in your answer I can't tell what you have, but I can tell you for sure that what Belinda wrote yesterday; i.e.,
[(w-1)/4]² =
(w² -2w +1)/16 is correct. That answer may be modified somewhat by certain arithmetic procedures but squaring w-1 MUST give, at least as a first step, w² -2w +1.

see dr.bob222
then why did the instructor say that this was wrong about
w2 -2w +1

he said it had to be:

w squared and negative one half w plus one over sixteen.



<b>We aren't working the same problem. And the reason for that is that you didn't use parentheses correctly. You are working this problem. </b>

(w-(1)/(4))^2

<b> Written as you should have written it is
[w-(1/4)]²

</b><I> That give you
w² - 0.5w + 1/16 which agrees with your previous answer and the teacher's answer.</I>

<b>I worked this one</b>

[(w-1)/4]²

<b>which gives the answer I posted yesterday.</b>
(w² -2w + 1)/16

<I>I hope this clears things up.