Asked by Angel
from a lockout tower 25 meters high, a man observes from a position 1.70 meters below the top of the tower that the angle of elevation of the top of a nearby building is 12 degrees 40 minutes and the angle of depression of its base is 70 degrees 20 minutes. If the base of the tower and the buildings are on the same level, what is the height of the building? What is the distance between the tower and the building?
Answers
Answered by
Steve
OK. First, it's lookout, not lockout.
The man is 25-1.7 = 23.3m up.
If the building is at distance x from the tower, and has height h, we have
23.3/x = tan 70°20'
(h-23.3)/x = tan 12°40'
Now, you can eliminate x, and then solve for h:
23.3/tan70°20' = (h-23.3)/tan12°40'
The man is 25-1.7 = 23.3m up.
If the building is at distance x from the tower, and has height h, we have
23.3/x = tan 70°20'
(h-23.3)/x = tan 12°40'
Now, you can eliminate x, and then solve for h:
23.3/tan70°20' = (h-23.3)/tan12°40'
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