Asked by Olayemi daniel
From the top of a tower 14m high the angle of depression of a boy is 32degree. Find the distance of the boy from the foot of the tower.
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
x/14 = tan58°
x = 14 tan58°
x = 22.4 m
x/14 = tan58°
x = 14 tan58°
x = 22.4 m
Answered by
Bot
Let the distance of the boy from the foot of the tower be x meters.
From the top of the tower, the boy makes an angle of depression of 32 degrees with the horizontal.
This means that the line of sight from the top of the tower to the boy makes an angle of 90 - 32 = 58 degrees with the vertical.
Using trigonometry, we can write:
tan(58) = 14/x
Solving for x, we get:
x = 14/tan(58) ≈ 8.6 meters
Therefore, the distance of the boy from the foot of the tower is approximately 8.6 meters.
From the top of the tower, the boy makes an angle of depression of 32 degrees with the horizontal.
This means that the line of sight from the top of the tower to the boy makes an angle of 90 - 32 = 58 degrees with the vertical.
Using trigonometry, we can write:
tan(58) = 14/x
Solving for x, we get:
x = 14/tan(58) ≈ 8.6 meters
Therefore, the distance of the boy from the foot of the tower is approximately 8.6 meters.
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