Question

9. The reaction of 50 mL of N2 gas with 150 mL H2 gas to form ammonia via the equation: N 2(g) + 3H2 (g) → 2NH3 (g) will produce a total of mL of ammonia if pressure and temperature are kept constant

Answer 1

P V = n R T

V = n (R T/V0
so volume is proportional to number of mos if P and T are constant

we need three mols of H2 for every mol of N2 so there is exactly the right amount of each

for every mol of N2 we will get 2 mol of NH3
so for every mL of N2 we will get 2 mL of NH3
so for 50 mL of N2 we will get 100 mL of NH3