Question
Please show me how to work! thanks
When Snno2(s) is formed form the comustion of gray tin, the reaction enthalpy is -578.6 kJ, and when white tin is burned to form SnO2(s), the reaction enthalpy is -580.7 kJ. Calculate the reaction enthalpu for Sn(gray)-->Sn(white)
When Snno2(s) is formed form the comustion of gray tin, the reaction enthalpy is -578.6 kJ, and when white tin is burned to form SnO2(s), the reaction enthalpy is -580.7 kJ. Calculate the reaction enthalpu for Sn(gray)-->Sn(white)
Answers
**SNO2(s)
Sn<sub>grey</sub> + O2 ==> SnO2 -578.6
SnO2 ==> Sn<sub>white</sub> + O2 580.7
-----------------------------
Add the two equations
Sn<sub>grey</sub> ==> Sn<sub>white</sub>
I have turned equation 2 around and changed the sign of dHf.
SnO2 ==> Sn<sub>white</sub> + O2 580.7
-----------------------------
Add the two equations
Sn<sub>grey</sub> ==> Sn<sub>white</sub>
I have turned equation 2 around and changed the sign of dHf.
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