Calculate the molarity of sulfuric acid if 25.00 mL of 0.095 mol L NAOH reacts with 26.45 mL of the acid.

Answer 1

2NaOH + H2SO4 --> Na2SO4 + 2H2O

mols NaOH = mols x L = ?
mols H2SO4 = 1/2 mols H2SO4 (look at the coefficients in the balanced equation).
M H2SO4 = mols H2SO4/L H2SO4