Question
Calculate the molarity of 1 lit solution of 93% H2SO4 by weight by volume even the density of solution is 1.84 g/ml
Answers
DrBob222
mass of 1L of the solution is
grams = 1.84 g/mL x 1000 mL = 1840g
mass H2SO4 in that 1840 g is
1840 x 0.93 = ?
mols H2SO4 = ?g H2SO4/molar mass H2SO4.
M H2SO4 = mols/L
grams = 1.84 g/mL x 1000 mL = 1840g
mass H2SO4 in that 1840 g is
1840 x 0.93 = ?
mols H2SO4 = ?g H2SO4/molar mass H2SO4.
M H2SO4 = mols/L
M
17.5