Asked by chris
an object moving on the x axis with a constant acceleration increases its x coordinate by 108 m in a time of 9.5 s and has a velocity of 20 m/s at the end of this time.
Determine the acceleration of the object during this motion?
Determine the acceleration of the object during this motion?
Answers
Answered by
Damon
v = Vi + a t
20 = Vi + 9.5 a
d = Vi t + (1/2) a t^2
108 = (20-9.5 a) (9.5) + (1/2) a (9.5)^2
solve for a
20 = Vi + 9.5 a
d = Vi t + (1/2) a t^2
108 = (20-9.5 a) (9.5) + (1/2) a (9.5)^2
solve for a
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