Asked by Lorine
Find an equation of the tangent line to the graph at the given point.
3(x2 + y2)2 = 100(x2 − y2), (4, -2)
3(x2 + y2)2 = 100(x2 − y2), (4, -2)
Answers
Answered by
Damon
6 (x^2+y^2)(2x+2ydy/dx)=100(2x-2ydy/dx)
find dy/dx at (4,-2)
6(16+4)(8-4dy/dx)=100(8+4dy/dx)
solve for dy/dx which is m in y = m x + b
then use the given point in the given equation to find b
find dy/dx at (4,-2)
6(16+4)(8-4dy/dx)=100(8+4dy/dx)
solve for dy/dx which is m in y = m x + b
then use the given point in the given equation to find b
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