Asked by Danielle
A swimmer heads directly across a river, swimming at 1.5 m/s relative to the water. She arrives at a point 30 m downstream from the point directly across the river, which is 87 m wide.
(c) In what direction should the swimmer head so as to arrive at the point directly opposite her starting point?
(c) In what direction should the swimmer head so as to arrive at the point directly opposite her starting point?
Answers
Answered by
Ms. Sue
Did you see Sheenybeany's response?
http://www.jiskha.com/display.cgi?id=1407609411
http://www.jiskha.com/display.cgi?id=1407609411
Answered by
Damon
First crossing:
time to cross = 87/1.5 = 58 seconds
so speed of current = 30/58 = .517 m/s
second crossing
v upstream = 1.5 sin A = .517
sin A = .345
A = 20.2 degrees
then if they ask:
v across = 1.5 cos A
time to cross = 87/1.5 = 58 seconds
so speed of current = 30/58 = .517 m/s
second crossing
v upstream = 1.5 sin A = .517
sin A = .345
A = 20.2 degrees
then if they ask:
v across = 1.5 cos A
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