Asked by Kitty
                The approximate distance, s, in feet that an object falls in t seconds when dropped from a height is obtained by use of the tormula s = 16r^2. In 8 seconds, the object will fall
A. 15384 feet
B. 1024 feet
C. 256 feet
D. None of these
            
        A. 15384 feet
B. 1024 feet
C. 256 feet
D. None of these
Answers
                    Answered by
            Damon
            
    aaarrrggghhhh, feet and inches and stuff :(
anyway
if g = -32 ft/s^2
then I will have to admit that the distance fallen from a still start is
s = 16 t^2
(not r^2 by the way, falls straight down, not in a circle)
s = 16 (64) = 1024 answer B
which we did not need a calculator for because we have
s = 2^4 * 2^3 * 2^3
which is 2^10
which we all know is
1024
    
anyway
if g = -32 ft/s^2
then I will have to admit that the distance fallen from a still start is
s = 16 t^2
(not r^2 by the way, falls straight down, not in a circle)
s = 16 (64) = 1024 answer B
which we did not need a calculator for because we have
s = 2^4 * 2^3 * 2^3
which is 2^10
which we all know is
1024
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