Asked by me
A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).
Answers
Answered by
Reiny
slope of the line going through the first two points
= (-7-9)/(-12-8) = -16/-20 = 4/5
so going through new point (-5,-15) with the same slope
y+15 = (4/5)(x+5)
do whatever you have to do further, but that is in
point-slope form
= (-7-9)/(-12-8) = -16/-20 = 4/5
so going through new point (-5,-15) with the same slope
y+15 = (4/5)(x+5)
do whatever you have to do further, but that is in
point-slope form
Answered by
riri
udk
Answered by
Anonymous
line passes through ( 1, -5 ) and ( -3, 7).
a.) Write an equation for the line point-slope form.
B, Rewrite the equation in slope-intercept form.
a.) Write an equation for the line point-slope form.
B, Rewrite the equation in slope-intercept form.
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