Asked by Mariel
The Angle of depression of Boat A from the top of a cliff which is 32 m high is 24 degree 15 minutes .The angle of depression of Boat B from the same point is 18 degree 12 minutes .Find distance between the two side with diagram
Answers
Answered by
Henry
h = 32 m.
A = 24.25o
B = 18.2o
Tan24.25 = h/X1 = 32/X1
X1*Tan24.25 = 32
X1 = 32/Tan24.25 = 71 m.=Hor. distance
between boat A and the cliff.
Tan18.2 = h/(X1+X2) = 32/(71+X2)
(71+X2)*Tan18.2 = 32
71+X2 = 32/Tan18.2 = 97.33
X2 = 97.33-71 = 26.3 m=Distance between
boat A and B.
A = 24.25o
B = 18.2o
Tan24.25 = h/X1 = 32/X1
X1*Tan24.25 = 32
X1 = 32/Tan24.25 = 71 m.=Hor. distance
between boat A and the cliff.
Tan18.2 = h/(X1+X2) = 32/(71+X2)
(71+X2)*Tan18.2 = 32
71+X2 = 32/Tan18.2 = 97.33
X2 = 97.33-71 = 26.3 m=Distance between
boat A and B.
Answered by
Angie
Thank you for this idea 😍
Answered by
Vanilla
Thanks it helps a lot
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