Asked by JR
How many liters of nitrogen oxide at STP are produced from the reaction of 59.g of NH3?
Balanced Equation:
Ammonia reacts with oxygen to produce nitrogen oxide and water.
4NH3(g)+5O2(g)→4NO(g)+6H2O(g)
Balanced Equation:
Ammonia reacts with oxygen to produce nitrogen oxide and water.
4NH3(g)+5O2(g)→4NO(g)+6H2O(g)
Answers
Answered by
DrBob222
mols NH3 = 59/molar mass NH3 = ?
Convert mols NH3 to mols NO using the coefficients in the balanced equation. That's ?mols NH3 x (4 mols NO/4 mols NH3) = ? x 1/1 = ?mols NO.
Then ? mols NO x 22.4L/mol = x L NO @ STP
Convert mols NH3 to mols NO using the coefficients in the balanced equation. That's ?mols NH3 x (4 mols NO/4 mols NH3) = ? x 1/1 = ?mols NO.
Then ? mols NO x 22.4L/mol = x L NO @ STP
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