Asked by frank
                how many liters of a 10%solution of acid should be added to 20 liters of 60%solution of acid to obtain a 50%solution?
            
            
        Answers
                    Answered by
            Ms. Sue
            
    This looks like a chemistry assignment.
    
                    Answered by
            DrBob222
            
    Assuming the density doesn't change and the solutions mix with no volume change, the following should do it. 
L = liters we need to add.
L(10) + 20(60) = (L+20)*50
Solve for L.
    
L = liters we need to add.
L(10) + 20(60) = (L+20)*50
Solve for L.
                    Answered by
            DrBob222
            
    Frank=
You should show the subject matter in the heading. In this case the heading should have been chem or math. Had it not been for Ms Sue, I wouldn't have looked at anything called journal assignment
    
You should show the subject matter in the heading. In this case the heading should have been chem or math. Had it not been for Ms Sue, I wouldn't have looked at anything called journal assignment
                    Answered by
            NAGAPRIYA NAGANABOINA
            
    how many liters of a 10%solution of acid should be added to 20 liters of 60%solution of acid to obtain a 50%solution
    
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