Question

mr. lee had a bag of red beans and a bag of black beans. 20% of the total number of beans were black, and there were 180 ounces more red beans than black beans. he transferred some red beans to the bag containing black beans, so that, the bag now contained 30% of the total number of beans. How many ounces of beans were there in the bag of mixed beans

Answer 1

r = b+180
b = .2(r+b)
so,
b = 60
r = 240
Total beans = 300 oz

After the transfer, 30% = 90 oz

So, that means that 30 oz of red beans were transferred, added to the 60 oz of black beans already there.

Answer 2

X oz. of black beans.

(X+180) oz. of red beans.

Total = X + (X+180) = 2x + 180.

X/(2x+180) = 0.20
x = 0.4x + 36
0.6x = 36
X = 60 Oz. of Black beans.

X+180 = 60+180 = 240 Oz. of red beans.

Total = 60 + 240 = 300 oz. of beans.

0.3 * 300 = 90 oz. of mixed beans.

Answer 3

pawg

Answer 4

Is this actually correct?