Asked by Elisa
A jet airliner moving initially at 300 mi/h due east enters a region where the wind is blowing at 100 mi/h in a direction 26.0° north of east. What is the new velocity of the aircraft relative to the ground?
in m/h at degrees North of east.
in m/h at degrees North of east.
Answers
Answered by
drwls
Add the following two vectors:
300 i (the air speed of the plane);
100 cos26 i + 100 sin26 j (wind speed relative to ground)
The sum is 389.0 i + 43.8 j
That a means 389 mph velocity component in the east direction and 43.8 mph in the north direction. Take the square root of the sum of the two swuares for the speed, and the arctan of 43.8/389 for the direction north of east.
300 i (the air speed of the plane);
100 cos26 i + 100 sin26 j (wind speed relative to ground)
The sum is 389.0 i + 43.8 j
That a means 389 mph velocity component in the east direction and 43.8 mph in the north direction. Take the square root of the sum of the two swuares for the speed, and the arctan of 43.8/389 for the direction north of east.
Answered by
Elisa
thank you.
Answered by
CHARAKUPAH
Superb work
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.