Asked by Christopher
A boat sails 40km from point A to point B, east of A on a lake. Lodge P is south of point A. Another lodge Q is south of point B. The bearing of Q from point A is S52degresE and the bearing of P from B is S39degresW.
If P is 60km from Q, calculate the bearing of lodge Q from lodge P.
Help me understand this question.
If P is 60km from Q, calculate the bearing of lodge Q from lodge P.
Help me understand this question.
Answers
Answered by
Damon
tan(90-39) = AP/40
so
AP = 49.4
tan (90-52) = BQ/40
so
BQ = 31.2
so
P is (49.4-31.2) or 18.1 km south of Q and 40 km west of q
tan theta = 40/18.1
theta = 65.7 degrees east of north from P to Q
so
AP = 49.4
tan (90-52) = BQ/40
so
BQ = 31.2
so
P is (49.4-31.2) or 18.1 km south of Q and 40 km west of q
tan theta = 40/18.1
theta = 65.7 degrees east of north from P to Q
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