Question
1. A boat sails for 4 hours at 35 mph in a direction 135degrees 51'. how far shouth has it sailed (to the nearest mile)?
Is it 96 miles??
2. A ship travels 55 km on a bearing of 11degrees, and then travels on a bearing of 101degrees for 133 km. find the distance of the end of the trip from the starting point to the nearest kilometer.
Im not sure about this one!
Is it 96 miles??
2. A ship travels 55 km on a bearing of 11degrees, and then travels on a bearing of 101degrees for 133 km. find the distance of the end of the trip from the starting point to the nearest kilometer.
Im not sure about this one!
Answers
Reiny
On the assumption that you consider NORTH to have a bearing of 0 and 135 is a clockwise rotation from there, you would have a triangle with the x-axis as one side, the hypotenuse as 140 miles and you want the vertical side of that triangle,
so sin 45 = x/140
x = 140/sin45
= 198
for the second one, after making a sketch I found the angle between the two paths to be 90 degrees, so we want to find the hypotenuse of a right-angled triangle with sides 55 and 133
h^2 = 55^2 + 133^2
h = 143.9
so sin 45 = x/140
x = 140/sin45
= 198
for the second one, after making a sketch I found the angle between the two paths to be 90 degrees, so we want to find the hypotenuse of a right-angled triangle with sides 55 and 133
h^2 = 55^2 + 133^2
h = 143.9