Question
What is the energy of the photon emitted when the electron in a hydrogen atom drops from energy level E5 to energy level E2?
Answers
DrBob222
E = R(1/n^2 - 1/n^2)
R = 1.097E7*(1/4 - 1/25)
R = 1.097E7*(1/4 - 1/25)