Asked by charles
What is the mass of water obtained when mix 100.0 mL of 2.5 M. HNO3 with 100.0 mL of 2.55 M. KOH?
Answers
Answered by
DrBob222
HNO3 + KOH ==. KNO3 + H2O
mols HNO3 = M x L = 2.5 x 0.1 = 0.25
mols KOH = 2.55 x 0.1 = 0.255
Since the reaction is a 1:1 ratio, the HNO3 is the limiting reagent and 0.25 mols H2O will be produced.
g H2O = mols H2O x molar mass H2O = ?
mols HNO3 = M x L = 2.5 x 0.1 = 0.25
mols KOH = 2.55 x 0.1 = 0.255
Since the reaction is a 1:1 ratio, the HNO3 is the limiting reagent and 0.25 mols H2O will be produced.
g H2O = mols H2O x molar mass H2O = ?
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