Asked by Tina
1. Water with a mass of 2kg is held at constant volume in a pressure cooker. 10,000 J of energy is added from the heater inside the pressure cooker. The container is not terribly well insulated, so the container leaks 2000 J of energy to the surrounding air. What is the total change in the systems internal energy?
here are the equations we can use:
(-m1)(C1)(ΔT1)=(m2)(C2)(ΔT2)
Q=mcΔT
Q=mL
ΔU=Q-W
W=PΔV
There might be others I am forgetting...sorry
Please indicate which equation you use and why you used it. Thanks!
here are the equations we can use:
(-m1)(C1)(ΔT1)=(m2)(C2)(ΔT2)
Q=mcΔT
Q=mL
ΔU=Q-W
W=PΔV
There might be others I am forgetting...sorry
Please indicate which equation you use and why you used it. Thanks!
Answers
Answered by
bobpursley
changeU=Qadded-loss(W)
changeU=10,000-2000 J
changeU=10,000-2000 J
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