Asked by Utibe

The fourth and ninth term of an a.p are -3 and 12 repectively find:the common different and the sum of the first seven term.

Answers

Answered by Reiny
a+3d = -3
a+8d = 12
subtract:
5d = 15
d = 15/5 = 3

a + 9 = -3
a = -12

common difference is 3
sum(7) = (7/2)(-24 + 6(3)) = -21
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