A 2.0-kg object starts from rest from the top of an inclined plane that makes an angle of 30° with the horizontal and has a rise of 0.40 m. It slides down the inclined plane and at the bottom has a kinetic energy of 60 J. Ignore friction and use g = 10 m/ .

Answer 1

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Answer 2

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Answer 3

You problem does not make sense to me.
If it slides down a vertical distance of .4 meters then we can calculate the kinetic energy
(1/2) m v^2 = m g h
(1/2)(2)v^2 = 20 (.4) = 8 Joules, not 60 joules.
Moreover you asked for nothing, just stated impossible facts.