A 2.0 kg object starts from rest from the top of an inclined plane that makes an angle of 30 degrees with the horizontal and has a rise of .4m. It slides down the inclined plane and at the bottom has a kinetic energy of 60J. Ignore friction and use g = 10.m/s2. what is the speed of the object at the bottom of the inclined plane?
4 answers
0.45
Evaporations is water turning into air and making clouds.
34
The energy at the bottom will be equal to Kinetic Energy. PE=0
Use KE =(1/2)mv^2
60 J = (1/2)(2 kg)v^2
60 J = v^2
v = 7.7 m/s
Use KE =(1/2)mv^2
60 J = (1/2)(2 kg)v^2
60 J = v^2
v = 7.7 m/s
3 answers