Asked by Claire
A 42.0 kg swimmer with an initial speed of 1.50 m/s decides to coast until she comes to rest. If she slows with constant acceleration and stops after coasting 2.00 m, what was the magnitude of the force exerted on her by the water?
Answers
Answered by
Henry
F = m*a
a = (V^2-Vo^2)/2d
a = (0-(1.5^2))/4 = -0.5625 m/s^2.
F = 42 * (-0.5625) = -23.63 N.
The negative sign means the force opposes the motion.
a = (V^2-Vo^2)/2d
a = (0-(1.5^2))/4 = -0.5625 m/s^2.
F = 42 * (-0.5625) = -23.63 N.
The negative sign means the force opposes the motion.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.