Ask a New Question

Question

Show that the derivative of y= cosh-1 (2x-1) is:
dy/dx = √1/(x2-x)
11 years ago

Answers

Steve
well, we know that d/dx arccosh u = 1/√(u^2-1) du

So just use the chain rule, and note that

(2x-1)^2-1 = 4x^2-4x
11 years ago

Related Questions

How do I take the derivative in respect to c1 for the following utility function? u1 = log(c1) +... what is the derivative of y=ln(x/4) What is the first derivative of ln (x^2 + 2)? Would the first derivative of R(t)=9t[(t-4)^3/2.718] be R'(t)=3.311258278(3(t-4)^2(t)+(t-4)^3) and... what is the first derivative of the function u(S/(K+S)) = G(S) when u and K are constants? What is the derivative of Ae^kt*cos(wt+b)? What is the derivative of x^(x^2+1)? what is the derivative G(s) = s^2/(k^2+s^2)? (k^2+s^2)(2s)-s^2(2K+2S)/(K^2+S^2)^2 is this correct? derivative of f(x)=2 cot (4e^x) show that the derivative of f(x) = ax^2 +bx+c is 2ax+b What is the derivative of cot^2x^3
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use