Question
Show that the derivative of y= cosh-1 (2x-1) is:
dy/dx = √1/(x2-x)
dy/dx = √1/(x2-x)
Answers
Steve
well, we know that d/dx arccosh u = 1/√(u^2-1) du
So just use the chain rule, and note that
(2x-1)^2-1 = 4x^2-4x
So just use the chain rule, and note that
(2x-1)^2-1 = 4x^2-4x