Asked by help

what is the derivative of y=ln(x/4)
Answered by Steve
if y=ln(u)

y' = 1/u u'

y = ln(x/4)
y' = 1/(x/4) * 1/4 = 4/x * 1/4 = 1/x

makes sense, since ln(x/4) = lnx - ln4
so, y' = 1/x