Asked by help
what is the derivative of y=ln(x/4)
Answers
Answered by
Steve
if y=ln(u)
y' = 1/u u'
y = ln(x/4)
y' = 1/(x/4) * 1/4 = 4/x * 1/4 = 1/x
makes sense, since ln(x/4) = lnx - ln4
so, y' = 1/x
y' = 1/u u'
y = ln(x/4)
y' = 1/(x/4) * 1/4 = 4/x * 1/4 = 1/x
makes sense, since ln(x/4) = lnx - ln4
so, y' = 1/x
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