Asked by Khusbu
If d length n breath of a rectangle r increased by 10% then by wt %wiil the area increase?
Answers
Answered by
MathMate
If the shapes are similar, area increase as the square of the ratio of the lengths.
In this case, the shape remains the same,
so
old area = d*n
new area = (1.1d)(1.1n)
= (1.1)² dn
= (1.1)² old area
Percentage increase in area
= 1.1²-1
= 21%
In this case, the shape remains the same,
so
old area = d*n
new area = (1.1d)(1.1n)
= (1.1)² dn
= (1.1)² old area
Percentage increase in area
= 1.1²-1
= 21%
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