The short answer is yes, because it all depends on the initial velocity and direction of the apple throw.
Is that what the question wants? There are multiple answers unless some more constraints are imposed.
Is that what the question wants? There are multiple answers unless some more constraints are imposed.
First, we can calculate the time it takes for the apple to hit the ground using the equation:
h = (1/2) * g * t^2
Where:
h = height of the student above the ground = 5.0 m
g = acceleration due to gravity = 9.8 m/s^2 (assuming we are on Earth)
t = time taken for the apple to fall
Rearranging the equation to solve for t, we get:
t = √(2h / g)
Substituting the values, we have:
t = √(2 * 5.0 m / 9.8 m/s^2) ≈ √(1.02) ≈ 1.01 s
Now, we can calculate the horizontal distance the car travels during this time.
Distance = velocity * time
Given that the velocity of the car is 3 m/s and the time is 1.01 s, we have:
Distance = 3 m/s * 1.01 s ≈ 3.03 m
Comparing the horizontal distance traveled by the car (3.03 m) with the length of the car (3.0 m), we can conclude that the apple will hit the teacher's car because it falls directly above it.