Asked by John

Sulphuric acid (H2SO4) solution reacts with magnesium metal (Mg) to
magnesium sulphate and hydrogen according to:
H2SO4 + Mg → MgSO4 + H2
How many litres of 5.00 M sulphuric acid would be required to dissolve
20.00 g of magnesium and how many mol of hydrogen would be
produced?
(RMM data: H = 1.01, S = 32.07, O = 16.00, Mg = 24.31)

Answers

Answered by DrBob222
mols Mg = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Mg to mols H2SO4.
Then M H2SO4 = mols H2SO4/L H2SO4. You know mols and M, solve for L.

Using mols Mg, convert to mols H2 for part 2.
Answered by Anonymous
m,mm
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions