Asked by Shontelle
John exerts constant force of 120 N for 10 s. on a stalled motorcycle. The final velocity is 8 m/s after the force was applied. If original velocity was zero, what is a)change of momentum b) the impulse produced c) magnitude of the mass of motorcycle
a&b) Impulse=deltaP=(120)(8)= 960
c.) how do I solve for magnitude of mass?
a&b) Impulse=deltaP=(120)(8)= 960
c.) how do I solve for magnitude of mass?
Answers
Answered by
Damon
a) No
true a) the same as b)
but
impulse = F dt = delta (mv)
F dt = 120 N * 10 s = 1200 N s
The change of momentum is M (final velocity - 0)
so
1200 N s = M (8 m/s)
so
M = 150 N s^2/m
which is 150 kg
note
N force =Mass (m/s^2)
so
N s^2/m = M in kilograms
8 m =
true a) the same as b)
but
impulse = F dt = delta (mv)
F dt = 120 N * 10 s = 1200 N s
The change of momentum is M (final velocity - 0)
so
1200 N s = M (8 m/s)
so
M = 150 N s^2/m
which is 150 kg
note
N force =Mass (m/s^2)
so
N s^2/m = M in kilograms
8 m =
Answered by
Michel
Thanks for correcting me, I got the values wrong xD
Answered by
Shontelle
lol Michel working on the same prob. as me.
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