Question

Calculate the amount of heat required to heat a 3.0kg gold bar from 23 degrees Celsius to 60 degrees Celsius

Answer 1

q needed = mass Au x specific heat Au x (Tfinal-Tinitial)

Answer 2

Need to use 2 sig fig. Git 3.6x10 to the 1power. Computer says wrong. Any clues?

Answer 3

What did you use for specific heat Au? with units?

Answer 4

I'm guessing here since I don't know what you used for specific heat Au and what units you want the answer. But my guess is you used specific heat in cal/g*C and that's about 0.032. delta T is 60-23 = 37. Then I think you failed to convert 3 kg Au to g Au so
3 x 0.032 x 37 = about 36 which is your answer. You should use 3000. Also note that your answer of 3.6E1 is not three significant figures.
3000 x 0.032 x 37 = 3.55E3 calories or close to that depending upon your value for sp.h.

Answer 5

0.128J

Answer 6

0.128J/g C

Answer 7

Requests answer in 2 sig fig not 3

Answer 8

Would that make it 3.6x10 to the 3?

Answer 9

I don't understand how you get 3.6 anything.
3000 x 0.128 x 37 = ?

Answer 10

.128x3000= 3.84x10E3 ?

Answer 11

Used 3.0x.128x37 which is difference os 23 to 60 degree change to get the 3.6

Answer 12

Need to drop kud at bday party will log in later

Answer 13

q = mass Au x specific heat Au x (Tfinal-Tinitial)
q = 3000 g x 0.128 J/g*c x 37C = 1.4 E4 J to two s.f.

If you multiply 3 x 0.128 x 37 you don't get 3.6. You get 14.2 BUT that 3 is not right. It is in kg and your specific heat unit is in J/g*c so you must change the 3 kg to 3000 g and use that.

Answer 14

Thanks DeBob222