Question
If a pitcher throws a fast ball with a speed of 35 m/s. The ball has a mass of 220 grams. a) how much work was done in throwing the ball? b) If the catcher catches the ball by moving his mitt 15 cm. backward what force did he exert?
a.) Throwing the ball in a positive direction
v= 35 m/s
m= .220 kg
wk= KE= 1/2 mv^2
wk= (1/2)(.220)(35)^2= 1.35x10^2
b.)When the pitcher moves mitt backwards, that would be a negative distance? d= -0.15 m.
F.d= change in KE
-0.15F= 0-((1/2)(0.220)(35)^2))
F= 8.98x10^2 N
a.) Throwing the ball in a positive direction
v= 35 m/s
m= .220 kg
wk= KE= 1/2 mv^2
wk= (1/2)(.220)(35)^2= 1.35x10^2
b.)When the pitcher moves mitt backwards, that would be a negative distance? d= -0.15 m.
F.d= change in KE
-0.15F= 0-((1/2)(0.220)(35)^2))
F= 8.98x10^2 N
Answers
MathMate
All correct!