monkey is accelerating down string whose breaking strength is two third of its weight the min acceleration of monkey should be A 1/3g B 2/3g C G d ZERO

Answer 1

Net force on monkey:

Fnet = weight - tension = mg - T

Newton's 2nd Law:

mg - T = ma

Solve for "T":

T = m(g-a)

To avoid breaking, T can be no more than 2/3 of monkey's weight:

T ≤ (2/3)mg

Substitute "m(g-a)" for T:

m(g-a) ≤ (2/3)mg

Solve this inequality for "a":

a ≥ (1/3)g

Answer 2

Good

Answer 3

let the weight of monkey is mg then maximum tension in rope be 2 mg/3 now using Newton 2nd law mg_T =ma mg_2/3mg=ma 1/3 mg=ma 1/3g=a