Question

Suppose that an accelerating car goes from 0 mph to 58.6 mph in five seconds. Its velocity is given in the following table, converted from miles per hour to feet per second, so that all time measurements are in seconds. (Note: 1 mph is 22/15 feet per sec = 12/15 ft/s.) Find the average acceleration of the car over each of the first two seconds.
t 0 1 2 3 4 5
v(t) 0.00 29.32 50.82 66.45 78.18 86.00

Answer 1

first second
a = change in V/change in t
= 29.32/1

second second
a = (50.82-29.32) /1

Answer 2

Edit:
first second
a = change in V/change in t
= 29.32/1 ft/s^2

second second
a = (50.82-29.32) /1 ft/s^2

ft/s^2 are the units