Asked by adii
a mass is thrown vertically upwards with an initial velocity of 30m/s. a second mass is dropped 0.5s later from directly above the height of 60m from the mass. when do they meet and at what height?
Answers
Answered by
bobpursley
first object:
hf=30t-4.9t^2
second object:
hf=60-4.9(t-.5)^2
since they meet at hf, set them equal, solve for tf.
for height, put that tf back into either equation, solve for tf.
hf=30t-4.9t^2
second object:
hf=60-4.9(t-.5)^2
since they meet at hf, set them equal, solve for tf.
for height, put that tf back into either equation, solve for tf.
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