Question

The stay at a hotel on Spring Break is normally distributed with a mean of 7 days and a standard deviation of 2 days. If 8000 people visited this hotel on Spring Break...

a) If a visitor stays 6 days what is the corresponding z-score?
b) How many visitors stayed less than 6 days?
c) What percent of the visitors stay less than 4 days?
a)
z-score for 6 days = (6-7)/2 = -1/2 = -.5

b)
go to your table at z = -.5 and find the corresponding probability , multiply by 8000
( I got 2468

c) repeat the above for 4 days

I found this website a great replacement for tables
http://davidmlane.com/hyperstat/z_table.html

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