Asked by Katie
                What is the period, in seconds, of a simple pendulum of length 3 meters? 
Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places
Please help! A step by step would with the answer would be helpful!
            
        Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places
Please help! A step by step would with the answer would be helpful!
Answers
                    Answered by
            Steve
            
    surely you have the formula for the period of a pendulum of length L (and small amplitude):
T = 2π √(L/g)
Now just plug in your numbers.
    
T = 2π √(L/g)
Now just plug in your numbers.
                    Answered by
            D man
            
    the answer is 3.48
    
                    Answered by
            Anonymous
            
    the guy up top stupid the answer is wrong 
    
                    Answered by
            Jay
            
    D man is correct, it is 3.48.
    
                    Answered by
            Vic
            
    3.48 just like what D man said
    
                    Answered by
            2019 wassup
            
    4.49 
    
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