Asked by Katie

What is the period, in seconds, of a simple pendulum of length 3 meters?

Use the gravitational constant g = 9.8 m/s2 and round your answer to two decimal places

Please help! A step by step would with the answer would be helpful!
Answered by Steve
surely you have the formula for the period of a pendulum of length L (and small amplitude):

T = 2π √(L/g)

Now just plug in your numbers.
Answered by D man
the answer is 3.48
Answered by Anonymous
the guy up top stupid the answer is wrong
Answered by Jay
D man is correct, it is 3.48.
Answered by Vic
3.48 just like what D man said
Answered by 2019 wassup
4.49